Let the cost of a 2-inch marble be \( x \) dollars. Since the 1-inch marbles cost 30 cents less than the 2-inch marbles, the cost of a 1-inch marble would be \( x - 0.30 \) dollars.
Rochelle buys 25 1-inch marbles for a total of $10. Therefore, we can set up the following equation:
\[ 25 \times (x - 0.30) = 10 \]
Now, simplify and solve for \( x \):
\[ 25x - 7.50 = 10 \]
Adding \( 7.50 \) to both sides gives:
\[ 25x = 17.50 \]
Now, divide by 25:
\[ x = \frac{17.50}{25} = 0.70 \]
So, the cost of a 2-inch marble is \( 0.70 \) dollars, or 70 cents.
Thus, the answer is:
$0.70