Many metals react with oxygen gas to form the metal oxide. For example calcium reacts:
2Ca(s) + O2(g)--> 2CaO(s)
Calculate the mass of calcium prepared from 4,20g of Ca and 2.80g of O2. (a) How many moles of CaO can form from the given mass of Ca?
4.20 g Ca x (1 mole Ca/40.08 g) = ?? moles Ca. Moles CaO are same since 2 moles Ca produce 2 mols CaO.
(b) How many moles of CaO can form from the given mass of O2?
2.80 g O2 x (1 mole O2/32 g ) = ?? moles O2. Moles CaO will be twice moles O2 since 1 mole O2 produces 2 moles CaO
(c)What is the limiting reactant?
The limiting reagent is the one producing the smaller number of moles of CaO.
(d) How many grams of CaO can be formed?
Smaller number moles CaO x molar mass CaO = grams CaO formed.
Many metals react with oxygen gas to form the metal oxide. For example calcium reacts:
2Ca(s) + O2(g)--> 2CaO(s)
Calculate the mass of calcium prepared from 4,20g of Ca and 2.80g of O2. (a) How many moles of CaO can form from the given mass of Ca? (b) How many moles of CaO can form from the given mass of O2? (c)What is the limiting reactant? (d) How many grams of CaO can be formed?
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