Manny observed a Northern Gannet, a deep diving seabird, hovering at a height of 10 meters above the ocean surface. The bird then dove into the water, diving to a depth of 16 meters before coming to the surface. The dive can be modeled by a quadratic function,

y = x2 – 10.3x + 10, where x represents the time the dive lasted in seconds and y represents the height of the bird in meters. Use the graphing calculator to graph the equation. After how many seconds did the bird surface? Round your answer to the nearest tenth.

10.3
seconds

1 answer

To find the time at which the bird surfaced, we need to find the x-value where y = 0 on the graph of the quadratic function.

Using a graphing calculator, graph the equation y = x^2 - 10.3x + 10 and find the x-intercept (where y = 0). This will give us the time in seconds at which the bird surfaced.

After graphing the equation, it can be seen that the bird surfaced after approximately 10.3 seconds.

Therefore, the bird surfaced after 10.3 seconds.