let radius be r inches
let the height be h inches
vol = πr^2h
166.25 = πr^2 h
h = 166.25/(πr^2)
"economical cylinder" is a function of the surface area, SA
SA = 2 circles + rectangles of the side
cost = 2(2πr^2) + 6(2πrh)
= 4πr^2 + 12πrh
= 4πr^2 + 12πr(166.25/(πr^2))
= 4πr^2 + 1995/r
d(cost)/dr = 8πr - 1995/r^2 = 0 for a max/min of SA
8πr = 1995/r^2
r^3 = 249.375/π
r = appr 4.298 inches
h = appr 2.865 inches
check my arithmetic
Making a cylinder is costing your company $2/in^2 for top and bottom and $6/in^2 for the body(side). If the cylinder is to have 166.25oz volume, what are the most economical cylinder that you can make and what will be the cost of making it.
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