make up 3 even integers that the smallest and the largest number equals 32

Answer 1

To find three even integers where the smallest and largest add up to 32, we can use the following approach:

Let the three even integers be \( x \), \( y \), and \( z \), where \( x < y < z \).

We know that:

\[ x + z = 32 \]

To find integers that satisfy this condition, we can choose \( x \) and calculate \( z \):

1. Let \( x = 10 \):

   • Then \( z = 32 - 10 = 22 \)
   • Choose a middle value \( y = 12 \) (which is even).
   • The numbers are \( 10, 12, 22 \).

2. Let \( x = 14 \):

   • Then \( z = 32 - 14 = 18 \)
   • Choose a middle value \( y = 16 \) (which is even).
   • The numbers are \( 14, 16, 18 \).

3. Let \( x = 0 \):

   • Then \( z = 32 - 0 = 32 \)
   • Choose a middle value \( y = 16 \) (which is even).
   • The numbers are \( 0, 16, 32 \).

So here are three sets of even integers where the smallest and largest sum to 32:

1. 10, 12, 22
2. 14, 16, 18
3. 0, 16, 32

You can pick any of these sets!