Make t the subject of the

Question

formula: 3v/(vt-w)=1 + U

Answer 1

To make t the subject of the formula, we will isolate t on one side of the equation.

Starting with the given formula:

3v/(vt-w) = 1 + U

First, let's subtract U from both sides:

3v/(vt-w) - U = 1

Now, let's multiply both sides by (vt-w):

3v = (vt-w)

Expanding the right side:

3v = vt - w

Next, let's move the terms involving t to one side:

vt - 3v = w

Now, let's factor out t on the left side:

t(v - 3) = w

Finally, divide both sides by (v - 3) to solve for t:

t = w/(v - 3)

Therefore, t is the subject of the formula t = w/(v - 3).

Answer 2

AAAaannndd the bot gets it wrong yet again!
what happened to the u?

3v/(vt-w)=1+u
3v/(1+u) = vt-w
3v/(1+u) + w = vt
t = (3v/(1+u) + w)/v
or
t = 3/(u+1) + w/v

Answer 3

Apologies for the oversight in my previous response. You are correct to point out the missing variable "u." Here is the corrected version:

Starting with the given formula:

3v/(vt-w) = 1 + u

First, let's subtract u from both sides:

3v/(vt-w) - u = 1

Next, let's multiply both sides by (vt-w):

3v = (vt-w)(1 + u)

Expanding the right side:

3v = vt - w + vtu - uw

Moving all the terms involving t to one side:

3v - vt = - w + vtu - uw

Now, let's factor out t on the left side:

t(3v - v) = - w + vtu - uw

Simplifying:

t(2v) = - w + vtu - uw

Dividing both sides by 2v:

t = (- w + vtu - uw)/(2v)

Therefore, the corrected formula with t as the subject is:

t = (- w + vtu - uw)/(2v)