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If (70)x = 1, we need to find the value of x that satisfies this equation. To find x, we can use logarithms.
Using the logarithmic property that states logbx = y is equivalent to x = by, we can rewrite the equation as:
x = log₁₀1/70
Using the logarithmic property logbx = log₁₀x / log₁₀b, we can rewrite the equation further as:
x = log₁₀1 / log₁₀70
Since log₁₀1 equals 0 and log₁₀70 is a positive number, x would be 0 divided by a positive number, which is equal to 0.
Therefore, the only possible value of x that satisfies the equation (70)x = 1 is x = 0.
1 answer
To find the value of x that satisfies the equation (70)x = 1, we can use logarithms. Using the logarithmic property logbx = y, we can rewrite the equation as x = log₁₀1/70. Additionally, using the logarithmic property logbx = log₁₀x / log₁₀b, we can simplify further and rewrite the equation as x = log₁₀1 / log₁₀70. Since log₁₀1 equals 0 and log₁₀70 is positive, x would be 0 divided by a positive number, which is equal to 0. Therefore, the only possible value of x that satisfies the equation is x = 0.