Make n the subject of the formula

E=√x(n-x)/n-1

2 answers

It's hard to see just what you meant. I'll assume you meant
E=√(x(n-x)/(n-1))
Then that gives
E^2 = x(n-x)/(n-1)
(n-1)E^2 = x(n-x)
E^2n - E^2 = xn - x^2
(E^2-x)n = E^2-x^2
n = (E^2-x^2)/(E^2-x)

If I parsed it wrong, maybe you could either (a)
use some parentheses to clear things up, and then
(b) follow similar steps on your own to arrive at the desired result.
A=E^2-x^2/E^2-x