Could you answer this question?
Major car park has 3 levels. Each level has 6 rows and each row has 10 spaces. The charge for each space is $5 per day. The maximum total revenue for each day is therefore...
What did you do to get $900 ?
Now repeat the same for the given problem.
Major car park has y levels. Each level has n rows and each row has n spaces. The charge for each space is $x per day. The maximum total revenue for each day is therefore...
4 answers
So basically... there are different ways to answer this problem? Like... it's an open-ended question?
Huh?
If you have y levels, each level has n rows, and each row has n spaces. The charge for each space is $x per day. The maximum total revenue for each day is
$ynnx or $(y)(n^2)(x) or $n^2 xy
In my actual example, did you not notice that I multiplied the data numbers to get the cost of $900
that is, (3)(6)(10)(5) = 900
If you have y levels, each level has n rows, and each row has n spaces. The charge for each space is $x per day. The maximum total revenue for each day is
$ynnx or $(y)(n^2)(x) or $n^2 xy
In my actual example, did you not notice that I multiplied the data numbers to get the cost of $900
that is, (3)(6)(10)(5) = 900
I just understood that a day ago... thanks to the example you gave me
0 answers