You have to work with piles = x
4x + 2 = 5x +1
x = 3 if you substitute you have 14 dimes
3 piles of 4 = 12 plus 2 = 14
3 piles of
Maize counted her dime.when she put them in groups of 4 ,she had two dimes left over.when she put them in group of 5,she had one left over.what is the smallest number of dimes she could have.if she has more than 10?
5 answers
Sorry.. I didn't mean to post that.
the answer gives us x =1 not 3
and we get to 6 dimes, but your problem is talking about more than 10 dimes.
The one pile works because you have
4(1)+ 2 = 5(1) + 1
6 =6 .
Now, we have to find a multiple that will work...
Do you need more help from here?
the answer gives us x =1 not 3
and we get to 6 dimes, but your problem is talking about more than 10 dimes.
The one pile works because you have
4(1)+ 2 = 5(1) + 1
6 =6 .
Now, we have to find a multiple that will work...
Do you need more help from here?
Joshua gave warren a birthday present,how much ribbon did he need to go around the present and make the bow?the bow took 12 inches by itself.
"when she put them in groups of 4 ,she had two dimes left over"
---> 6 10 14 18 22 26 30 34 38 42 46 50 ...
"when she put them in group of 5,she had one left over"
----> 6 11 16 21 26 31 36 41 46 51 ...
ahhh, looks like 46
---> 6 10 14 18 22 26 30 34 38 42 46 50 ...
"when she put them in group of 5,she had one left over"
----> 6 11 16 21 26 31 36 41 46 51 ...
ahhh, looks like 46
actually, I just noticed that 26 works first.