No, Mack is not correct. Natural numbers are a subset of the rational numbers, not irrational numbers.
Natural numbers are the positive integers: \(1, 2, 3, \ldots\). Rational numbers are any numbers that can be expressed as a fraction \(\frac{a}{b}\) where \(a\) and \(b\) are integers and \(b \neq 0\). Since any natural number \(n\) can be expressed as \(\frac{n}{1}\), all natural numbers are indeed rational.
Irrational numbers, on the other hand, are numbers that cannot be expressed as a fraction of two integers. Examples include \(\pi\) and \(\sqrt{2}\). Therefore, natural numbers are not a subset of irrational numbers; they are a subset of rational numbers.
2 answers