during acceleration for 6s (9/1.5): s = 0.75 6^2 = 27m
during deceleration for 1.5s (9/6): s = 9*1.5 - 3*1.5^2 = 6.75m
total time: 6 + (120-27-6.75)/9 + 1.5 = 17 1/12 seconds
machines
A winding drum raises a cage through a height of 120 m. the cage has, at first, an accelerationof 1.5 m/s^2 until the velocity of 9 m/s is reached, after which the velocity is constant until the cage nears the top, when the final retardation is 6 m/s^2. Find the time taken for the cage to reach the top
2 answers
Aap chapter ko bhejna hai mujhe bhi
6 answers