It must be when
GM1/x^2=GM2(78-x)^2
solve fdr x
The value of M3 has no significance.
M1 = 45.0 kg is a spherical mass at the origin. M2 = 16.6 kg is also a spherical mass, and is located on the x-axis at x = 78.0 m.
At what value of x would a third mass M3 = 15.5 kg experience no net gravitational force due to M1 and M2?
1 answer