To perform a 270° counterclockwise rotation of the point \( M(6, -2) \), we can use the rotation formula. The general rule for rotating a point \( (x, y) \) counterclockwise around the origin by an angle \( \theta \) degrees is:
\[ (x', y') = (x \cos \theta - y \sin \theta, x \sin \theta + y \cos \theta) \]
For a 270° rotation, we can use the trigonometric values:
\[ \cos(270°) = 0 \] \[ \sin(270°) = -1 \]
Now, applying this to the point \( (6, -2) \):
\[ x' = 6 \cdot 0 - (-2) \cdot (-1) = 0 - 2 = -2 \] \[ y' = 6 \cdot (-1) + (-2) \cdot 0 = -6 + 0 = -6 \]
Thus, the coordinates of \( M' \) after a 270° counterclockwise rotation are:
\[ M'(-2, -6) \]
So, the final answer is:
\[ \boxed{(-2, -6)} \]