Lulu marks the points (9,1) and (-3,6) on a coordinate plane. What is the distance between these two points, rounded to the nearest tenth of a unit?

3 answers

To find the distance between the points \( (9, 1) \) and \( (-3, 6) \), we can use the distance formula, which is given by

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Here, we set:

  • \( (x_1, y_1) = (9, 1) \)
  • \( (x_2, y_2) = (-3, 6) \)

Now, we substitute the coordinates into the formula:

\[ d = \sqrt{((-3) - 9)^2 + (6 - 1)^2} \]

Calculating \( (-3) - 9 \) gives us:

\[ -3 - 9 = -12 \]

Now, squaring it:

\[ (-12)^2 = 144 \]

Next, we calculate \( 6 - 1 \):

\[ 6 - 1 = 5 \]

Now, squaring this value:

\[ 5^2 = 25 \]

Now, we substitute these squared values back into the distance formula:

\[ d = \sqrt{144 + 25} \]

Adding the two values inside the square root:

\[ 144 + 25 = 169 \]

Taking the square root gives us:

\[ d = \sqrt{169} = 13 \]

Thus, the distance between the points \( (9, 1) \) and \( (-3, 6) \) is

\[ \boxed{13.0} \]

when rounded to the nearest tenth.

What the mid point
Mb thought I was replying to my own thing now I look stupid