Lulu marks the points (9,1) and (-3,6) on a coordinate plane. What is the distance between these two points, rounded to the nearest tenth of a unit?(1 point)

Responses

7.2 units
7.2 units

13.0 units
13.0 units

8.0 units
8.0 units

14.2 units
14.2 units
Question 2
What is the midpoint of the segment? If not a whole number, write as a decimal(1 point)
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1 answer

To find the distance between the points (9,1) and (-3,6), we can use the distance formula, which is:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Here, \( (x_1, y_1) = (9, 1) \) and \( (x_2, y_2) = (-3, 6) \).

Plugging in the values:

\[ d = \sqrt{((-3) - (9))^2 + (6 - 1)^2} \] \[ = \sqrt{(-12)^2 + (5)^2} \] \[ = \sqrt{144 + 25} \] \[ = \sqrt{169} \] \[ = 13 \]

So, the distance between the two points is 13.0 units.


Now, let's find the midpoint of the segment connecting the two points. The midpoint \( M \) is given by the formula:

\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

Using the same points:

\[ M = \left( \frac{9 + (-3)}{2}, \frac{1 + 6}{2} \right) \] \[ = \left( \frac{6}{2}, \frac{7}{2} \right) \] \[ = (3, 3.5) \]

Thus, the midpoint of the segment is \( (3, 3.5) \).

To summarize:

  • Distance: 13.0 units
  • Midpoint: \( (3, 3.5) \)