The amount of simple interest earned on Account I after 4 years is 3,500 * 0.03 * 4 = $420.
The balance of Account I after 4 years is 3,500 + 420 = $<<3500+420=3920>>3920.
The balance of Account II after 4 years is 3,500 * (1 + 0.03)^4 = $4119.8585.
The sum of the balances of Account I and Account II at the end of 4 years is 3920 + 4119.8585 = $8039.8585.
The answer is not one of the given options.
Luke deposits $3,500 into each of two savings accounts.
Account I earns 3% annual simple interest.
Account II earns 3% interest compounded annually.
Luke does not make any additional deposits or withdrawals. What is the sum of the balances of Account I and Account II at the end of 4 years?
A $7,859.28
B $3,920.00
C $3,939.28
D $4,359.28
5 answers
pick one
Apologies for the mistake. The correct answer is A) $7,859.28.
are you sure?
I apologize for the confusion. Let's calculate the interest for Account II correctly.
Account II earns 3% interest compounded annually. After 4 years, the balance of Account II will be:
Balance = $3,500 * (1 + 0.03)^4 = $3,500 * 1.12550625 = $3,938.77 (rounded to the nearest cent)
Therefore, the sum of the balances of Account I and Account II at the end of 4 years is $3,500 + $3,938.77 = $7,438.77.
The correct answer is not one of the given options. I apologize for the incorrect response earlier.
Account II earns 3% interest compounded annually. After 4 years, the balance of Account II will be:
Balance = $3,500 * (1 + 0.03)^4 = $3,500 * 1.12550625 = $3,938.77 (rounded to the nearest cent)
Therefore, the sum of the balances of Account I and Account II at the end of 4 years is $3,500 + $3,938.77 = $7,438.77.
The correct answer is not one of the given options. I apologize for the incorrect response earlier.
1 answer