To find the costs for both plans based on the number of movies watched \( x \), we can define the monthly cost functions for both plans:
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Plan A: \[ A(x) = 20 + 1x = 20 + x \]
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Plan B: \[ B(x) = 12 + 3x \]
Next, we will graph these two functions and determine the intervals where Plan A is cheaper than Plan B. To find this interval, we need to solve the inequality:
\[ A(x) < B(x) \]
Substituting in the functions we derived earlier:
\[ 20 + x < 12 + 3x \]
Now, we will solve for \( x \):
- Subtract \( x \) from both sides:
\[ 20 < 12 + 2x \]
- Subtract 12 from both sides:
\[ 8 < 2x \]
- Divide by 2:
\[ 4 < x \] or \[ x > 4 \]
This means that Plan A is cheaper than Plan B when Luis watches more than 4 movies per month.
Summary:
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Plan A is cheaper than Plan B for \( x > 4 \).
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To visualize this, you can graph both linear functions on the same coordinate system:
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Plan A (linear line starting at (0, 20) with a slope of 1).
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Plan B (linear line starting at (0, 12) with a slope of 3).
Where the line representing Plan A is below the line for Plan B indicates the intervals of \( x \) values where Plan A is cheaper. The point at which they intersect occurs when \( x = 4 \).
Intervals:
- Plan A is cheaper when \( x > 4 \) (Luis watches more than 4 movies per month).