A=2.22
B=3.48
A + B = 8
2.22A x 3.48B = 21.54
solve for B
Luis bought eight bags of candy at the store for a total price of $21.54. He bought some bags of candy that cost $2.22 each and the rest cost $3.48 each. How many bags of the $3.48 candy did Luis buy?
3 answers
C means cheap candy bag, E means expensive candy bag.
C*2.22+E*3.48=21.54
C+E=8
C*2.22+E*3.48=21.54
C+E=8
I got this far, but how do I solve for B?