Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

Question

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

5 feet below
5 feet below

5 feet above
5 feet above

2.5 feet below
2.5 feet below

0 feet above or below

Answer 1

To determine how far above or below street level Luca’s initial launching point is, we need to analyze the given formula:

\[ y = -16t^2 + 40t - 5 \]

In this equation:

• \( y \) represents the height of the object above or below street level (in feet).
• \( t \) represents the time in seconds after the object is launched.

The initial launching point corresponds to the value of \( y \) when \( t = 0 \).

Substituting \( t = 0 \) into the formula, we get:

\[ y = -16(0)^2 + 40(0) - 5 \] \[ y = 0 - 0 - 5 \] \[ y = -5 \]

This means that the launching point is 5 feet below street level, as the y-coordinate is negative.

Therefore, the response is:

5 feet below.