Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

Question

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

5 feet below
5 feet below

5 feet above
5 feet above

0 feet above or below
0 feet above or below

2.5 feet below

Answer 1

To find how far above or below street level Luca’s initial launching point is using the formula \(y = -16t^2 + 40t - 5\), we can analyze the equation at \(t = 0\), which represents the initial launching point.

Substituting \(t = 0\) into the equation:

\[ y = -16(0)^2 + 40(0) - 5 \] \[ y = -5 \]

This means that at the moment of launch, the object's height \(y\) is \(-5\) feet. Therefore, Luca’s initial launching point is 5 feet below street level.

So, the correct response is:

5 feet below.