Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5

Question

. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

0 feet above or below
0 feet above or below

5 feet above
5 feet above

5 feet below
5 feet below

2.5 feet below
2.5 feet below

Answer 1

To analyze Luca's launching point using the given formula, \( y = -16t^2 + 40t - 5 \), we can look at the \( y \)-intercept of the equation. The \( y \)-intercept occurs at \( t = 0 \), which will tell us how far above or below street level Luca's initial launching point is.

Substituting \( t = 0 \) into the equation:

\[ y = -16(0)^2 + 40(0) - 5 \]

This simplifies to:

\[ y = -5 \]

Therefore, when Luca launches the object, he is 5 feet below street level.

Thus, the answer is:

5 feet below.