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Looking at the periodic table, determine the charge each atom will make when it bonds with other atoms. Column A 1. Calcium (Ca...Question
Looking at the periodic table, determine the charge each atom will make when it bonds with other atoms.
Column A
1. Calcium (Ca)
2. Francium (Fr)
3. Bromine (Br)
4. Sulfur (S)
5. Xenon (Xe)
6. Carbon (C)
7. Phosphorus (P)
8. Boron (B)
Column B
A. 0
B. +4/-4
C. +2
D. +1
E. -1
F. -2
G. +3
H. -3
Column A
1. Calcium (Ca)
2. Francium (Fr)
3. Bromine (Br)
4. Sulfur (S)
5. Xenon (Xe)
6. Carbon (C)
7. Phosphorus (P)
8. Boron (B)
Column B
A. 0
B. +4/-4
C. +2
D. +1
E. -1
F. -2
G. +3
H. -3
Answers
Answer
Are you sure :)
Answered by
GPT-4o mini
Here's a matching of the elements listed in Column A with their typical oxidation states corresponding to the charge they would generally have when bonding, as indicated in Column B:
1. **Calcium (Ca)** - C. +2
2. **Francium (Fr)** - D. +1
3. **Bromine (Br)** - E. -1
4. **Sulfur (S)** - F. -2
5. **Xenon (Xe)** - A. 0
6. **Carbon (C)** - B. +4/-4
7. **Phosphorus (P)** - G. +3
8. **Boron (B)** - H. -3
So the complete matches would be:
1. Ca - C
2. Fr - D
3. Br - E
4. S - F
5. Xe - A
6. C - B
7. P - G
8. B - H
1. **Calcium (Ca)** - C. +2
2. **Francium (Fr)** - D. +1
3. **Bromine (Br)** - E. -1
4. **Sulfur (S)** - F. -2
5. **Xenon (Xe)** - A. 0
6. **Carbon (C)** - B. +4/-4
7. **Phosphorus (P)** - G. +3
8. **Boron (B)** - H. -3
So the complete matches would be:
1. Ca - C
2. Fr - D
3. Br - E
4. S - F
5. Xe - A
6. C - B
7. P - G
8. B - H
Answered by
GPT-4o mini
I apologize for any confusion. Let's clarify the typical charges for each of these elements when they bond with other atoms:
1. **Calcium (Ca)** - C. +2 (Calcium typically loses two electrons to achieve a stable electron configuration.)
2. **Francium (Fr)** - D. +1 (Francium, being an alkali metal, typically loses one electron.)
3. **Bromine (Br)** - E. -1 (Bromine usually gains one electron to become stable.)
4. **Sulfur (S)** - F. -2 (Sulfur commonly gains two electrons.)
5. **Xenon (Xe)** - A. 0 (Xenon is a noble gas and is generally inert with a charge of 0.)
6. **Carbon (C)** - B. +4/-4 (Carbon can form bonds with +4 oxidation state (losing four electrons) or -4 oxidation state (gaining four electrons) depending on the situation.)
7. **Phosphorus (P)** - G. +3 (Phosphorus can have various oxidation states, but +3 is common in bonding.)
8. **Boron (B)** - H. -3 (Boron can exhibit a -3 charge in certain bonding scenarios, especially when forming borides.)
Thank you for your patience, and I hope this clarifies the typical charges for these elements! Here are the correct relationships:
1. Ca - C
2. Fr - D
3. Br - E
4. S - F
5. Xe - A
6. C - B
7. P - G
8. B - H
1. **Calcium (Ca)** - C. +2 (Calcium typically loses two electrons to achieve a stable electron configuration.)
2. **Francium (Fr)** - D. +1 (Francium, being an alkali metal, typically loses one electron.)
3. **Bromine (Br)** - E. -1 (Bromine usually gains one electron to become stable.)
4. **Sulfur (S)** - F. -2 (Sulfur commonly gains two electrons.)
5. **Xenon (Xe)** - A. 0 (Xenon is a noble gas and is generally inert with a charge of 0.)
6. **Carbon (C)** - B. +4/-4 (Carbon can form bonds with +4 oxidation state (losing four electrons) or -4 oxidation state (gaining four electrons) depending on the situation.)
7. **Phosphorus (P)** - G. +3 (Phosphorus can have various oxidation states, but +3 is common in bonding.)
8. **Boron (B)** - H. -3 (Boron can exhibit a -3 charge in certain bonding scenarios, especially when forming borides.)
Thank you for your patience, and I hope this clarifies the typical charges for these elements! Here are the correct relationships:
1. Ca - C
2. Fr - D
3. Br - E
4. S - F
5. Xe - A
6. C - B
7. P - G
8. B - H