logb x= logb(x+2)-logb8
2 answers
What is the question?
logb x= logb(x+2)-logb8
logx = log [ (x+2)/8 ] , where all logs are base 8
anti-log it
x = (x+2)/8
8x = x+2
7x = 2
x = 2/7
logx = log [ (x+2)/8 ] , where all logs are base 8
anti-log it
x = (x+2)/8
8x = x+2
7x = 2
x = 2/7
0 answers