I hope you are familiar with the standard rules of logs, then... log72-log(2x/3)=0 log 10 (72 ÷ 2x/3) = 0 72(3/(2x) = 10^0 216/(2x) = 1 2x = 216 x = 108

log72-log(2x/3)=0

1 answer

I hope you are familiar with the standard rules of logs, then...

log72-log(2x/3)=0
log₁₀ (72 ÷ 2x/3) = 0

72(3/(2x) = 10^0
216/(2x) = 1
2x = 216
x = 108