log5(x+3)+log5(x-2)=log5(14)

Answer 1

Log5(x+3)(x-2)=log5(14)
(X+3)(x-2)=14
X^2+x-6=14
X^2+x-20=0
(X+5)(x-4)=0
X=-5, x=4
-5 is not a true solution because you can't take the log of a negative number
X=4