Log5 (2x+1)=1

Answer 1

The logarithm of a number is the exponent by which another fixed value, the base, has to be raised to produce that number.

In this case the base is 5.

So you must solve equation:

5^(2 x + 1 ) = 1

Take the logarithm base 5 of both sides

2 x + 1 = 0

Subtract 1 to borh sides

2 x = - 1

x = - 1 / 2

Remark:

Logarithm of 1 = 0 for any base

Answer 2

Log5 (2x+1)=1
By definition, 5^Log5 (2x+1) = 2x+1, so now you have
2x+1 = 5
x = 2