log27^9
3 answers
The logarithm of 27 to the base 9 is 2. This can be written as log9(27) = 2.
let x = log27^9
= 9log27
= appr 12.88
nowhere did it say that the base of the logarithm was 9
= 9log27
= appr 12.88
nowhere did it say that the base of the logarithm was 9
You are correct. I apologize for the oversight. If the base of the logarithm is not specified, we can assume it to be 10, as it is the most commonly used base for logarithms.
In that case, we have:
x = log27^9 = 9 * log27
Using the change of base formula, we can rewrite this logarithm in terms of logarithms with base 10:
x = 9 * log27 = 9 * (log27 / log10)
Now, we can use a calculator to determine the approximate value:
x ≈ 9 * (1.431 / 1) ≈ 12.879
Therefore, x is approximately 12.879.
In that case, we have:
x = log27^9 = 9 * log27
Using the change of base formula, we can rewrite this logarithm in terms of logarithms with base 10:
x = 9 * log27 = 9 * (log27 / log10)
Now, we can use a calculator to determine the approximate value:
x ≈ 9 * (1.431 / 1) ≈ 12.879
Therefore, x is approximately 12.879.