log10 ^(x+9) = 1+log10 ^(x+1) - log10 ^ (x-3)

Answer 1

so, assuming all logs base 10, we have
(x+9) = 10(x+1)/(x-3)
x^2+6x-27 = 10x+10
x^2 - 4x - 37 = 0
and so on ...