log((x(sqrt�ã(X^2+1)/(x+1)^(2/3)))^6
Any ideas would be great, thanks
2 answers
that should be x times the square root of x squared plus one divided by( or fraction bar) x plus one raised to the 2/3 power, all raised to the power of 6
You will have to know the 3 main rules of logs
log (AB) = logA + logB
log(A/B) = logA - logB
log A^n = nlogA
so the outer exponent 6 can be brought down immediately to ge
6log(x√(x^2 + 1)/(x+1)^(2/3) )
= 6 ( logx + (1/2)log(x^2 + 1) - (2/3)log(x+1) )
= 6logx + 3log(x^2 + 1) - 4log(x+1)
log (AB) = logA + logB
log(A/B) = logA - logB
log A^n = nlogA
so the outer exponent 6 can be brought down immediately to ge
6log(x√(x^2 + 1)/(x+1)^(2/3) )
= 6 ( logx + (1/2)log(x^2 + 1) - (2/3)log(x+1) )
= 6logx + 3log(x^2 + 1) - 4log(x+1)
1 answer