2log(base2)3 is the same as log(base2)3^2, which would be log(base2)9.
Therefore, we have:
log(x/6) = log45
x/6 = 45
x = 45 * 6 = 270
log(base2)x-log(base2)6= log(base2)5+ 2log(base2)3
log(x/6)=3log15
(x/6)=15^3
6*(x/6)=15^3*6
x=15^3*6
=20,250
Answer is 270....
What did I do wrong...
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