log[3](7x-3)>=log[3](5x)

Answer 1

and the question is?

log3 (7x-3)- log3 (5x)M=0
log3( (7x-3)/5x)>=0
then
(7x-3)/5x >=1 (Remember 3⁰=1, so log3 1 =0)

7x-3>=5x
2x>=3
x>=3/2