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lnx+ln(x+1)=ln12

Find all real-roots

1 answer

ln[x(x+1)] = ln 12
x(x+1) = 12
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = -4 or x = 3
but lnx is only defined for x > 0, so

x = 3
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