Liz rushes down onto a subway platform to find her train already departing. She stops and watches the cars go by. Each car is 8.60 m long. The first moves past her in 2.05 s and the second in 1.73 s. Find the constant acceleration of the train.
_____m/(s^2)
Please explain this if possible. thanks!
2 answers
I will be happy to critique your work.
1st car =8.6/2.05 m/s =4.195m/s
2nd car = 8.6/1.73 m/s =4.971 m/s
4.971-4.195= 0.776m/s
a= delta V /delta T
(0.776m/s ) /0.32s= 2.44 m/(s^2)
That answer isn't correct. This is what I did initially and I'm stumped on this question. Please let me know if there's another way to do this question. :)
2nd car = 8.6/1.73 m/s =4.971 m/s
4.971-4.195= 0.776m/s
a= delta V /delta T
(0.776m/s ) /0.32s= 2.44 m/(s^2)
That answer isn't correct. This is what I did initially and I'm stumped on this question. Please let me know if there's another way to do this question. :)