I would do that this way.
Let X = candy from 3rd party.
(X/2)-3 = 5
Solve for X and I get 16 as follows:
Multiply through by 2
X-6=10 and X = 16 which means the boy had 16 going into the 3rd "robber."
How many into the second?
(X/2)-2 = 16
X-4=16
X = 4=32
X = 36 going into the second.
(X/2)-1 = 36
X-2=72
X = 74 to start.
Check it.
1/2 of 74 = 37 and 37-1=36
1/2 of 36 = 18 and 18-2 = 16
1/2 of 16 = 8 and 8-3=5.
Little Billy was out trick or treating on Halloween. He had gotten a lot of candy and was peering into his bag, when out from behind a tree came Freddy Krueger. Freddy reached into Billy's bag and took half of his candy plus one piece. Within a few steps, Billy encountered a Great White Shark, who reached into Billy's sack and took half of his remaining candy plus two pieces. Before Billy could turn and run, a Ninja Turtle, stole half of the candy that was left plus three pieces. Now Little Billy began to cry because he only had 5 pieces of candy left. How many pieces of candy did Billy have before Freddy, the Shark, and the Ninja Turtle raided his sack?
4 answers
74
Just wondering how many people came here because their teacher gave u guys this problem?
2(5+3) = 16
2(16+2) = 36
2(36+1) = 74
Billy had 74 pieces of candy at the beginning.
2(16+2) = 36
2(36+1) = 74
Billy had 74 pieces of candy at the beginning.