6Li(s)+N2(g)→2Li3N(s)
mols N2 = 59.6 x *1 mol/22,400 L) = approx 0.0027 but that's an estimate.
mols Li = mols N2 x (6 mols Li/1 mol N2) = approx 0.0027 x 6 = ?
Then g Li = mols Li x atomic mass Li = ?
Post your work if you get stuck.
Lithium reacts with nitrogen gas according to the following reaction:
6Li(s)+N2(g)→2Li3N(s)
What mass of lithium (in g) is required to react completely with 59.4 mL of N2 gas at STP?
1 answer
1 answer