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Question

A golf club charges $10 to join and $5 per game. John paid more than $25 last week to play golf. How many games could he have played?

Question 9 options:

More than 3 games

Less than 3 games

No more than 3 games

3 games exactly
Solve for b

A=bh

solve for h
V=Lwh

Answer 1

To solve the problem, let's determine how many games John could have played given that he paid more than $25 last week.

1. Establish Costs:

   • Joining fee: $10
   • Cost per game: $5

2. Total Cost Calculation: Let \( g \) represent the number of games played. The total cost \( C \) can be expressed as: \[ C = 10 + 5g \]

3. Set Up the Inequality: Since John paid more than $25, we have: \[ 10 + 5g > 25 \]

4. Simplify the Inequality: Subtract 10 from both sides: \[ 5g > 15 \] Now, divide both sides by 5: \[ g > 3 \]

5. Interpretation: This means that the number of games \( g \) must be greater than 3.

Conclusion: John could have played more than 3 games.

Answer: More than 3 games

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Now, for the mathematical equations:

1. Solve for \( b \) in the equation \( A = bh \): \[ b = \frac{A}{h} \]

2. Solve for \( h \) in the equation \( V = Lwh \): \[ h = \frac{V}{Lw} \]

Feel free to ask if you need further information or additional questions!