y = 4(2(x-3/2))^2+1
shift right 3/2
horizontal shrink by 2
vertical stretch by 4
shift up 1
or
y=16(x-3/2)^2+1
shift right 3/2
vertical stretch by 16
shift up 1
List a sequence of transformations which maps the graph of y=x^2 to the image with equation y=4*(2x-3)^2 + 1
Please help
4 answers
I still do not understand, pardon me
Could u use the terms dilation, reflection and translation and the axes?
Could u use the terms dilation, reflection and translation and the axes?
stretch = dilation
shift = translation
there is no reflection involved.
It amazes me that you could not figure that out. I assume you know that x is horizontal and y is vertical...
shift = translation
there is no reflection involved.
It amazes me that you could not figure that out. I assume you know that x is horizontal and y is vertical...
Keith, please refrain from using different screen names.
Also, please mention that you are reposting the question, and reposting within a short time could mean duplicate efforts by tutors, and hence slow the answering process.
Your previous question has also been answered here:
http://www.jiskha.com/display.cgi?id=1482466342
Also, please mention that you are reposting the question, and reposting within a short time could mean duplicate efforts by tutors, and hence slow the answering process.
Your previous question has also been answered here:
http://www.jiskha.com/display.cgi?id=1482466342