Asked by Anonymous
Lisa, Malik and Nick had 630 sweets altogether. Lisa gave 1/3 of her sweets to Malik. Malik then gave 1/7 his the total number of sweets to Nick. Nick then gave 1/4 of his total number of sweets to Lisa. In the end, each of them had the same number of sweets. How many sweets did each child have at first?
Answers
Answered by
oobleck
L+M+N = 630
Lisa gave 1/3 of her sweets to Malik
L → 2/3 L
M → M + 1/3 L
Malik then gave 1/7 his the total number of sweets to Nick
M → 6/7 (M + 1/3 L)
N → N + 1/7 (M + 1/3 L)
Nick then gave 1/4 of his total number of sweets to Lisa
L → 2/3 L + 1/4 (N + 1/7 (M + 1/3 L))
N → 3/4 (N + 1/7 (M + 1/3 L))
Now equate the final values of L,M,N and solve
Lisa gave 1/3 of her sweets to Malik
L → 2/3 L
M → M + 1/3 L
Malik then gave 1/7 his the total number of sweets to Nick
M → 6/7 (M + 1/3 L)
N → N + 1/7 (M + 1/3 L)
Nick then gave 1/4 of his total number of sweets to Lisa
L → 2/3 L + 1/4 (N + 1/7 (M + 1/3 L))
N → 3/4 (N + 1/7 (M + 1/3 L))
Now equate the final values of L,M,N and solve
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