L+M+N = 630
Lisa gave 1/3 of her sweets to Malik
L → 2/3 L
M → M + 1/3 L
Malik then gave 1/7 his the total number of sweets to Nick
M → 6/7 (M + 1/3 L)
N → N + 1/7 (M + 1/3 L)
Nick then gave 1/4 of his total number of sweets to Lisa
L → 2/3 L + 1/4 (N + 1/7 (M + 1/3 L))
N → 3/4 (N + 1/7 (M + 1/3 L))
Now equate the final values of L,M,N and solve
Lisa, Malik and Nick had 630 sweets altogether. Lisa gave 1/3 of her sweets to Malik. Malik then gave 1/7 his the total number of sweets to Nick. Nick then gave 1/4 of his total number of sweets to Lisa. In the end, each of them had the same number of sweets. How many sweets did each child have at first?
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