To determine how much each box can weigh, we can denote the weight of each box as \( x \).
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Identify the maximum weight allowed in the elevator:
- The maximum weight allowed in the elevator is 2,000 pounds.
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Account for Lionel's weight:
- Lionel weighs 170 pounds. Therefore, the weight limit for the boxes themselves is: \[ 2000 \text{ pounds} - 170 \text{ pounds} = 1830 \text{ pounds} \]
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Calculate the weight for each box:
- There are 10 boxes, so the total weight of the boxes can be represented as \( 10x \). To not exceed the remaining weight limit, we set up the following inequality: \[ 10x \leq 1830 \]
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Solve for \( x \): \[ x \leq \frac{1830}{10} \] \[ x \leq 183 \]
So, each box can weigh a maximum of 183 pounds.
Graphing the Solution:
On a number line labeled "Weight of Each Box in the Elevator," you would plot:
- Closed point at 0 (representing that the weight can't be negative).
- A line extending from 0 to a closed point at 183 (since each box of books can weigh anywhere from 0 to 183 pounds).
The correct depiction on the number line given the options would thus be shown in the option with the range from 0 to 200 and closed points at 0 and 183.
Therefore, the answer is:
- An illustration shows a number line labeled Weight of Each Box in the Elevator. The number line ranges from 0 to 200 in 20 unit increments. A closed point is plotted at 0. A line extends from that point to the right, connecting with a closed point at 183.