circle center is (3,5)
lines intersect at (3,5) yay!
ring has area pi(64-25) = 39pi = 122.91
lines intersect at angle θ such that
tanθ = 2/3
θ = 33.69°
the 4 parts are divided into two pairs, each pair occupying half the circle.
33.69/180 = 0.187
so, the semicircles are divided into areas of 22.98 and 99.93
Lines y= 2x/3+3&y=5 cut the ring formed by circles (x-3)2+(y-5)2=64 and (x-3)2+(y-5)2=25 into four parts. Find the area of each of the four parts.
1 answer
1 answer