To solve the problem, we first note that since lines \( x \) and \( y \) are parallel, we can use properties of angles formed by a transversal intersecting parallel lines.
From the information given:
- \( B = 7x + 16 \)
- \( F = 3x + 28 \)
- \( D = 2y + 18 \)
Assuming \( B \) and \( F \) are corresponding angles or alternate interior angles, we set them equal to each other (since angles corresponding to parallel lines and a transversal are equal):
\[ 7x + 16 = 3x + 28 \]
Let's solve for \( x \):
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Subtract \( 3x \) from both sides: \[ 7x - 3x + 16 = 28 \] \[ 4x + 16 = 28 \]
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Subtract 16 from both sides: \[ 4x = 28 - 16 \] \[ 4x = 12 \]
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Divide by 4: \[ x = 3 \]
With \( x \) found, we substitute \( x = 3 \) into \( D \) in order to determine \( y \). However, we actually need to determine a relation for \( y \). Since \( D \) is equal to either \( B \) or \( F \) (again assuming some relationship here), we would also expect that \( D = 2y + 18 = 7x + 16 \) or \( D = 2y + 18 = 3x + 28 \).
Letβs use \( B \) since it involves \( 7x + 16 \):
- Substitute \( x = 3 \) back into \( B \): \[ B = 7(3) + 16 = 21 + 16 = 37 \]
So we set \( D \) equal to \( B \):
\[ 2y + 18 = 37 \]
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Subtract 18 from both sides: \[ 2y = 37 - 18 \] \[ 2y = 19 \]
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Divide by 2: \[ y = \frac{19}{2} = 9.5 \]
Finally, the solution gives us:
- \( x = 3 \)
- \( y = 9.5 \)
Thus, the values obtained are \( x = 3 \) and \( y = 9.5 \).