Lines tangent to the curve y-1=2x^2+3x pass through the point A(2,-1). Find the x-coordinate(s) of the point(s) of tangency.
The answer is 2+2^1/2, 2-2^1/2, I just don't know how to get there. Please help! Thank you!
The answer is 2+2^1/2, 2-2^1/2, I just don't know how to get there. Please help! Thank you!