For quadrilateral ABCD to be a rectangle, the diagonals must be equal in length. Therefore, we can set the lengths of the diagonals equal to each other:
\[ AC = BD \]
Substituting the expressions we have for the diagonals:
\[ x + 29 = 4x - 1 \]
Now, we will solve for \( x \). First, rearrange the equation:
\[ 29 + 1 = 4x - x \]
This simplifies to:
\[ 30 = 3x \]
Now, divide both sides by 3:
\[ x = 10 \]
Thus, the value of \( x \) that makes quadrilateral ABCD a rectangle is
\[ \boxed{10} \]