(x^2-1)y'+2y=(x+1)^2
y' + 2/(x^2-1) y = (x+1)/(x-1)
now use the integrating factor of
e^(∫(x+1)/(x-1) dx)
and things get simpler.
linear equations of order one
1. (x^2-1)dy/dx+2y=(x+1)^2
1 answer
1. (x^2-1)dy/dx+2y=(x+1)^2
1 answer