Let's translate the problem into a mathematical equation.
- Let the unknown number be represented by \( x \).
- The sum of the number and four can be expressed as \( x + 4 \).
- Four times this sum would be \( 4(x + 4) \).
On the other side:
- Three times the number is \( 3x \).
- Two less than this quantity is \( 3x - 2 \).
- Two multiplied by this result gives \( 2(3x - 2) \).
Now we can set up the equation: \[ 4(x + 4) = 2(3x - 2) \]
Now, let's solve the equation step by step.
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Distribute on both sides: \[ 4x + 16 = 6x - 4 \]
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Get all terms involving \( x \) on one side and constant terms on the other: \[ 4x - 6x = -4 - 16 \] \[ -2x = -20 \]
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Divide by -2: \[ x = 10 \]
Thus, the solution to the problem is: \[ \boxed{10} \]