If centre has (6,8) and one end of the diameter has (4,2), add Δx and Δy to the centre to get the other end of the diameter, namely,
(Δx,Δy) = (6-4, 8-2) = (2,6)
So the other end of the diameter would be (6+2,8+6)=(8,14).
Check: the mid-point of the diameter should be the centre:
((4+8)/2,(2+14)/2)=(6,8) = centre of circle.
line segment ab is the diameter of circle O whose center has coordinates (6,8) . what are the coordinates of point b if the coordinates of point a are (4,2)
6 answers
(1,3)
Answer= (1,3)
can you guys give me some answers
c'mon I don't see any answers y'all?
the answer is (8,14)