Line AB

contains point A(−4, 1)
and point B (−1, 3)
. Find the coordinates of A′
and B′
after a dilation with a scale factor of 2 with a center point of dilation at the origin

1 answer

To find the coordinates of points \( A' \) and \( B' \) after a dilation with a scale factor of 2 and with the center of dilation at the origin, we can use the formula for dilation:

\[ A' = (k \cdot x_A, k \cdot y_A) \] \[ B' = (k \cdot x_B, k \cdot y_B) \] where \( k \) is the scale factor, and \((x_A, y_A)\) and \((x_B, y_B)\) are the coordinates of points \( A \) and \( B \).

Given:

  • Point \( A(-4, 1) \)
  • Point \( B(-1, 3) \)
  • Scale factor \( k = 2 \)

Now, we will apply the dilation to both points:

  1. For Point A: \[ A' = (2 \cdot -4, 2 \cdot 1) = (-8, 2) \]

  2. For Point B: \[ B' = (2 \cdot -1, 2 \cdot 3) = (-2, 6) \]

Thus, the coordinates after the dilation are:

  • \( A'(-8, 2) \)
  • \( B'(-2, 6) \)

Therefore, the coordinates of points \( A' \) and \( B' \) after the dilation are:

  • \( A'(-8, 2) \)
  • \( B'(-2, 6) \)
Similar Questions
    1. answers icon 3 answers
  1. Two lines L1: 2y - 3x - 6 = 0 and L2: 3y + x - 20 = 0 interest at a point A.(a) find the coordinates of A. (b) A third line L3
    1. answers icon 2 answers
  2. Line L is given by the equation 3y+2x =9 and point P has coordinates (6,-5).a. Explain why point P is not on the Line L b. Find
    1. answers icon 3 answers
    1. answers icon 2 answers
more similar questions