Linda's teacher divided the class into groups of five and required each member of a group to meet with every other member of that group. How many meetings will each group have?
3 answers
I know the answer is 10, but the problem is I can't find out the formula :/ if I only show the answer I won't get any credit and it'll be marked wrong.
5 per group.
person x = 1st person meeting everyone
x - 1, x - 2, x - 3, x-4 (no x - 5 because he/she is 5th person).
Meeting count:4
second person meeting everyone = y
y - 1, y -2, y - 3,
(no y -4 or y - 5 because he/she already met with person x and cannot meet with himself)
Meeting count: 7
third person meeting everyone = z
z - 1, z - 2
z has already met with y, z has already met with x, z cannot meet him/herself.
Meeting count: 9
fourth person meeting everyone = k
k -1
k has already met with x,y, and z. k cannot meet with himself
Meeting count:10
everyone has met with each other
person x = 1st person meeting everyone
x - 1, x - 2, x - 3, x-4 (no x - 5 because he/she is 5th person).
Meeting count:4
second person meeting everyone = y
y - 1, y -2, y - 3,
(no y -4 or y - 5 because he/she already met with person x and cannot meet with himself)
Meeting count: 7
third person meeting everyone = z
z - 1, z - 2
z has already met with y, z has already met with x, z cannot meet him/herself.
Meeting count: 9
fourth person meeting everyone = k
k -1
k has already met with x,y, and z. k cannot meet with himself
Meeting count:10
everyone has met with each other
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1 answer