Asked by Margo
limit (x^2+y^2)/(x+y)^2 as (x,y)->(0,0)
I don't know how to prove it doesn't exist. Please help!
I don't know how to prove it doesn't exist. Please help!
Answers
Answered by
Alexa
Consider the line through the points (3,2,5) and (1,1,1). Consider the plane A that is perpendicular to this line, and passing through the point (-1,0,2). Consider the plane B that passes through the points (1,-1,0), (0,2,0), and (0,5,2). Consider the intersection of plane A and plane B. Write the equation of the line of intersection.
Answered by
math guy
type your equation onto the website wolfram alpha ... google the website if you're unfamiliar with it.
Answered by
Steve
along x=y, the expression is
2x^2/4x^2 = 1/2
along x=2y, we have
5y^2/9y^2 = 5/9
In other words, as we approach (0,0) along different paths, the limit varies, so cannot be said to exist as a single number.
2x^2/4x^2 = 1/2
along x=2y, we have
5y^2/9y^2 = 5/9
In other words, as we approach (0,0) along different paths, the limit varies, so cannot be said to exist as a single number.
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